Array in c++ vs c++ stl

This all are the static ways cause we have memory is created at compile time 

#include <iostream>

#include <array>

using namespace std;

void normPrint(int *arr,int (&aref)[5], int &m){

    // *arr is a pointer array which 

    // aref is another name of the original array a 

    // Note aref is not another array it is a another name

    cout<<"pass by pointer"<<endl;

    for(int i = 0;i<m;i++){

        cout<<arr[i]<<" ";

    }

    cout<<endl<<"pass by refernce variable"<<endl;

    for(int i = 0;i<5;i++){

        cout<<aref[i]<<" ";

    }

}

void stlPrint(array<int, 5> &arr, int m){

    cout<<"\n";

        for (int &element : arr) {

        cout<<element<<" "; 

    }

}

int main() {

    int arr[100] ={5,7,8,9,10};

    int a[] ={1,2,3,4,5};

    

    // this will give size as 100

    // not a good way

    // int n = sizeof(arr)/sizeof(arr[0]);

    int n = 5;

    normPrint(arr,a,n);

    

    // STL

   array<int, 5> myArray = {1, 2, 3, 4, 5};

   int m = myArray.size();

// Method 1

    // Using iterators to print the elements of the array

    for (auto it = myArray.begin(); it != myArray.end(); ++it) {

        cout << *it << " ";

    }

// Method2

    // This automatically iterates over the elements in the array, and there's no need to use explicit iterators.

    cout<<"\n";

    for(auto i:myArray){

        cout<<i<<" ";

    }

// Method3

// Using pass by refernce 

    stlPrint(myArray,m);

    return 0;

}